Question 16 of 20 Advanced Practical
How would you design controls to test whether a fluorescent organelle marker changes cell physiology?
Short answer
Compare labeled cells with unlabeled and empty-vector cells on the functions the organelle performs, at the expression level you actually use, and check that the phenotype of interest is the same in both. Then show the result does not depend on the marker by reproducing it with a second, independent label or a label-free method.
Why
A fluorescent marker is a protein the cell did not ask for. Overexpression can saturate import machinery, change organelle morphology, tether membranes together or titrate a binding partner. Dyes have their own problems.
Potential-sensitive mitochondrial dyes report the very property an experiment may be trying to measure, and they can themselves inhibit respiration at high concentrations. Phototoxicity adds a second layer, because illumination of a labeled organelle generates reactive oxygen species locally. The design therefore tests both the label and the imaging.
The key comparison is functional rather than visual. Mitochondrial labels are judged against respiration and membrane potential, lysosomal labels against pH and degradation, and all of them against growth rate and viability.
How to work it through
- Build matched arms: parental cells, empty vector or untagged fluorescent protein, and the organelle marker, all at the expression level you will use.
- Measure organelle function directly in each arm, for example oxygen consumption for mitochondria or a degradation assay for lysosomes.
- Measure general health in each arm, including growth rate, viability and cell cycle distribution.
- Image a labeled sample under your real acquisition settings and repeat the functional measurements immediately afterwards to capture phototoxicity.
- Repeat the key experimental finding with a second, structurally unrelated marker or with a label-free method such as phase contrast or a dye-free readout.
- Record expression level per cell, because the effect is usually dose dependent.
An example
A mitochondrially targeted red fluorescent protein is expressed in two pools, one sorted dim and one sorted bright. Oxygen consumption is unchanged in the dim pool but 25 percent lower in the bright pool, which also shows more fragmented mitochondria. The study uses the dim pool, confirms the drug-induced fission phenotype in unlabeled cells by electron microscopy, and reports expression level in the methods.
Where the answer stops holding
A functional panel can only test the functions it measures, so a subtle effect on an unmeasured process can remain. Transient expression gives a wide range of levels across cells, which blurs any threshold. Agreement between two markers does not exclude a shared artifact, such as competition for the same import pathway.
Label-free methods often have lower resolution, so the confirmation may be coarser than the original observation.
A strong answer covers
- Parental, vector and marker arms at the real expression level
- Direct functional assay for the organelle
- General health readouts: growth, viability, cycle
- Test phototoxicity under real imaging settings
- Reproduce with a second marker or a label-free method
Common mistakes
- Judging a marker harmless because the cells look normal down the microscope
- Using a bright, strongly overexpressing pool because the images are better
- Measuring membrane potential with a dye that itself depends on potential, without a control
The interviewer might ask next
How would you detect phototoxicity during a long time-lapse experiment?